Question

In how many ways 6 girls out of 12 girls in a class may be selected for a team so that 2 particular girls (captain and vice-captain) are always there? Select one: a. 210 b. 24 c. 360 d. 120

Answer 1

As two girls are already included we should select 4 from remaining 10

i.e...,

10C4 = 10*9*8*7/4*3*2*1 => 210

OPTION a

Answer 2

Answer:

Option A is correct .i.e., 210 ways to select 6 girls out of 12.

Step-by-step explanation:

Total no of girls = 12

We have to select 6 girls from total girls.

To find: No of ways we can select girls.

2 girls are fix in six girl , captain and vice captain.

⇒ we just have to select 4 girls from 10 girls.

No ways in which 4 girls is selected = $^{10}\textrm{C}_{4}=\frac{10!}{4!\times(10-4)!}$

                                                              = $\frac{10\times9\times8\times7\times6!}{4\times3\times2\times6!}$

                                                              = $10\times3\times7$

                                                              = 210

Therefore, Option A is correct .i.e., 210 ways to select 6 girls out of 12.