Question

in how many ways 7/12 can be written as a sum of two fractuon in lowest terms given that denominators of the two fraction are different and each is not morethan 12?​

Answer 1

Step-by-step explanation:

1/3+1/4, 2/6+2/8,3/9+3/12,

Answer 2

There are three ways can be written as a sum of two fraction in lowest terms given that denominators of the two fraction are different and each is not more than 12.

Step-by-step explanation:

We have,

Let two fraction are:

$\dfrac{1}{3}+\dfrac{1}{4}=\dfrac{7}{12}$

$\dfrac{2}{6}+\dfrac{2}{8}=\dfrac{14}{24}=\dfrac{7}{12}$

$\dfrac{3}{9}+\dfrac{3}{12}=\dfrac{21}{36}=\dfrac{7}{12}$

All denoinators are 12.

Hence, there are three ways can be written as a sum of two fraction in lowest terms given that denominators of the two fraction are different and each is not more than 12.