Math, asked by hafispk, 5 months ago

In how many ways 9 things can be distributed between 8 persons​

Answers

Answered by SurendraDappukota733
1

Answer:

2 ways

Step-by-step explanation:

first way is each thing to each person and second way is each person's take extra percentage remaining understand

Answered by khantharsh87
0

Answer:

Example:In how many ways can 9 balls be distributed equally among 3 children?

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If you don’t count the order in which a student recieves the balls, and just treat a group of balls a student has as one and the same depending on the elements (ex: a student having balls is the same as ), or as having , then there are ways.

A way to understand this is first ask yourself how many different combinations can the first student get.

He can have any of the first balls; possible balls for the first one, possible balls for the second one, and possible balls for the third one.

However, since the grouping is permutable, there are identical sets in our possible combinations. In fact, since for every set of numbers, there are other sets which contain the exact same numbers, there are only of unique sets. In other words, each set of numbers has permutations.

There are unique sets for the first person to acquire.

The second person now has a more limited choice. He can have any of the remaining balls.

There are possible combinations he can have.

But just as before, each set of numbers has permutations, so

he has only unique sets.

Finally, the last person only has possible unique set, since he is just dumped with whatever remaining balls were not acquired by the first or second person. You can also easily see he has possible combinations but there are permutations once again, so he has possible unique set.

Now by the , there are

different ways of dividing balls among people.

If for some odd reason we are not counting different permutations as identical, then the answer is simply (which would defeat the purpose of having people).

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