In how many ways a batsman can score 200 with only 4's and 6's
Answers
6's(33.3)because 200÷4 is 33.3
Answer:
The answer is 17 ways
Step-by-step explanation:
Let the no. of 4's be x and 6's be y
So, the eqn. is 4x+6y=200
Simplifying the eqn we get 2x+3y=100
2x=100-3y
Since we know that for the number to be divisible by 2, unit digit should be even number.
So, this means that 100-3y should give an even number and for that 3y should also be an even number.
Therefore 3y will be even when y=0,2,4,6,...... ----> EQN 1
So now since 2x cannot be a fraction as well as a negative number so the last multiple of 3 that is less than 100 is 96
i.e., 3y=96
y=32
so, in EQN 1, the arithmetic progression or y value will go to 32
y= 0, 2, 4, 6.......32
So in this AP,
First term, a=0
Last term, l=32
common difference, d=2
l=a+(n-1)d
32=0+(n-1)2
16=n-1
n=17
So, in 17 ways the batsman can score a double century