in how many ways, a committee of 5 members can be selected from 6 men and 5 ladies consisting of 3 men and 2 ladies?
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Hey there
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The correct answer is
Answer= 200
Explanation:
3 men out 6 and 2 ladies out 5 are to be chosen
Required number of ways = 6C3×5C2=
[6×5×4/3×2×1] × [5×4/2×1] = 200
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