Math, asked by ameer5285, 1 year ago

In how many ways a cricketer can score a double century (200




runs) with only boundaries (fours) and over boundaries (sixes)?




a.15



b. 16



c. 17



d. 18


ArcyStar123: This is not actually about asking. The thing is, if you consider no. of sixes never to be zero, the no. of ways will be 16. And one correction, the word 'between' after the A.P. calculations will be 'from'.

Answers

Answered by Elwin123
1
16 or 17 will be the answer i cannot give u a assurance
Answered by ArcyStar123
3

Taking the no. of fours and sixes to be x and y respectively,

we can say,

4x+6y=200

or x=(100-3y)/2

Now, x must belong to a whole number, thus we can say 3y<100 ,(3y≠100)

Thus max. value of y should be 33.

Now, regarding the equation, (100-3y) should be even, and thus y should also be even.

Thus, max. value of y is 32.

Now, by AP,

32=0+(n-1)2 ⇒n=17(no. of even terms from 32 to 0 is 17)

Thus, in 17 ways, the situation is possible.(Ans.-c)

If considered no.of sixes never to be zero, no.of ways=16 (Ans.-b)

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