Math, asked by raishu2603, 6 months ago

In how many ways can 10 chairs be divided and arranged for 2 cabins A and B with 4 and
6 chairs respectively?​

Answers

Answered by aaditya2333
23

Answer:

2

Step-by-step explanation:

2

Answered by amitnrw
1

Given :  10 chairs to be divided and arranged for 2 cabins A and B with 4 and 6 chairs respectively

To Find : Number of ways

Solution:

Either 4 chairs for cabin A  or 6 chairs for cabin B can be selected

in ¹⁰C₄  or ¹⁰C₆  ways  =  210 ways

Then 4 chairs can be arranged in 4! = 24 ways

and 6 chairs can be arranged in  6! = 720 ways

Hence total number of ways  

= 210 * 24 * 720

= 36,28,800  ways

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