In how many ways can 10 identical blankets be given to 3 beggars such that each receives at least one blanket
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I just thought a couple of answers.
Let, 1st beggar be x
2nd beggar be y
3rd beggar be z
here,(x+y+z) should be 10
or,(x+y+z) is 10, where,x/y/z =min.1
Thats the formula
Now, (3+3+4),(4+4+2), your wish.It can be done in a few ways.
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