Question

In how many ways can 10 lion and 6 tigers to be arranged in a row so that no two tigers are together ?

Answer 1

Answer:

Your answer is

Step-by-step explanation:

10 ! * 10^P6

Answer 2

Given :

Lion = 10

Tigers = 6

To find :

No. of ways in which they are arranged in a row so that no two tigers are together.

Solution :

_ L₁ _ L₂ _ L₃ _ L₄ _ L₅ _ L₆ _ L₇ _ L₈ _ L₉ _ L₁₀ _

Lions can be arranged in 10! ways

Total no. of vacant spaces = 11

T₁ has 11 places , T₂ has 10 places since T₁ and taken a place and similarly T₃ has 9 places , T₄ has 8 place , T₅ has 7 places and T₆ has 6 places.

Therefore tigers can be arranged in 11×10×9×8×7×6 ways

Therefore total no. of ways = 10! × (11×10×9×8×7×6)