Question

In how many ways can 10- paise coin, two 20 paise, three 25 paise and one 50 paise coins be distributed among 8 children so that each child gets only one coin?

Answer 1

Answer:

1680

Step-by-step explanation:

The total number of coins = 2 + 2 + 3 + 1 = 8.

2 coins are 10 paise, 2 coins are 20 paise, 3 coins are 25 paise and 1 coin is 50 paise.

The required number of ways =

$\frac{8!}{2!\:2!\:3!\:1!}=\frac{8*7*6*5*4*3*2*1}{2*1*2*1*3*2*1*1}\\ =8*7*6*5\\=1680$