Math, asked by arpandeep2002, 11 months ago

In how many ways can 12 books be arranged on a shelf if:

(a) 4 particular books must always be together.

(b) 2 particular books must occupy the first position and the last position.

Answers

Answered by sbadiwal05
10

Answer:

ans (a)= two ways

ans b = one way

Answered by amitnrw
26

Total number of Ways  = 9! * 4!  if 4 particular books must always be together. &  10! * 2 ways if 2 particular books must occupy the first position and the last position.

Step-by-step explanation:

Total Books = 12

(a) 4 particular books must always be together.

Take 4 books as 1   & remaining books = 8

Total Books = 9

9 books can be arranged in 9 !  ways

4 books as 1 can be arranged in 4!  ways

Total number of Ways  = 9! * 4!

(b) 2 particular books must occupy the first position and the last position.

2 Books can be arranged in 2! = 2  ways

Remaining 10 books can be arranged in 10!  Ways

Total number of Ways  = 10! * 2

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