Math, asked by miliyojpriyah, 1 year ago

In how many ways can 15 identical blankets be distributed among 6 beggars such that each gets atleast one blanket and two particular beggars get equal blankets and another three particular beggars get equal blankets? a) 10 b) 11 c) 12 d) 13

Answers

Answered by sreeja3
1
hi friend,

ans: b (11)

the possible ways are

* (2,2);(3,3,3);2--------(1)

* (3,3);(2,2,2);3-------(2)

* (4,4);(1,1,1);4----------(3)

* (1,1);(2,2,2);7---------(4)

* (2,2);(1,1,1);8---------(5)

* (2,2);(2,2,2);5------(6)

* (1,1);(1,1,1);10---------(7)

* (1,1);(3,3,3);4--------(8)

* (3,3);(1,1,1);6--------(9)

* (4,4);(2,2,2);1-------(10)

* (1,1);(4,4,4);1---------(11)

above are possible ways....
first two numbers for two persons equally. second two three person's equally.left one person given number for him.

hope it helps.....
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