In how many ways can 2 red beads, 3 blue beads, 2 yellow beads, and white beads be arranged in a necklace if the white beads stay together? (Circular Permutation)
Answers
Answer:
Since there are 4 kinds or colored beads then it would be:
(4–1)!/2
3!/2
3
And since some beads have similar color to other beads (2 yellow, 3 blue, 2 red)then we should group them together cause the condition says so. With that it would mean that they have their own arrangements inside while also being arranged outside.
2!3!2! x 3
72
So there are 72 ways
Ther overall formula I used is:
2!3!2! x (4–1)!/2
Answer:
In how many ways can 2 red beads, 3 blue beads, 2 yellow beads, and white beads be arranged in a necklace if 4. beads of the same color are placed together?
Since there are 4 kinds or colored beads then it would be:
(4–1)!/2
3!/2
3
And since some beads have similar color to other beads (2 yellow, 3 blue, 2 red)then we should group them together cause the condition says so. With that it would mean that they have their own arrangements inside while also being arranged outside.
2!3!2! x 3
72
So there are 72 ways
Ther overall formula I used is:
2!3!2! x (4–1)!/2