Question

In how many ways can 21 red balls and 19 blue balls are arranged in arow so that no two blue balls are together

Answer 1

Step-by-step explanation:

Let E - Position of red ball

Let H - Position of blue ball

In order to keep blue books that are never together, we must place all these books as:

H E H E H E H .... H E H

Since there are 21 balls on red , we can choose 22 places to place 19 blue ball.

22C19 = 22C3 = (22 x 21 x 20)/(3 x 2 x 1) = 1540 ways.

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