Question

in how many ways can 23 different books be given to 5 students so that 2 of the students will have 4 books each and other will have 5 books each​

Answer 1

Answer:

SOORY BUT YOUR QUESTION IS WRONG

Step-by-step explanation:

The 2 students can be selected in

5

C

2

ways.

Now, the first 5 books to be given to the first student can be done in

22

C

5

ways.

Similarily next 5 books can be selected in

17

C

5

ways.

Now the remaining 12 can be selected in 3 groups of 4 by

12

C

4

×

8

C

4

Hence, total =

5

C

2

×

22

C

5

×

17

C

5

×

12

C

4

×

8

C

4

I HOPE IT'S HELPFUL FOR YOU AND OTHERS

Answer 2

Concept

In mathematics, a combination is a selection of items from a set that has distinct members so that the order of selection does not matter.

Given

It is given that 23 different books are given to 5 students so that 2 of the students will have 4 books each and other will have 5 books each

Find

We need to find the total number of ways in which books can be distributed

Solution

The 2 students can be selected in 5C2 ways.

Now, the first 4 books to be given to the first student can be done in 23C4 ways.

Similarily next 4 books can be selected in 19C4 ways.

Now the remaining 15 can be selected in 3 groups of 5 by 15C5 * 10C5

Hence, total 5C2 * 23C4 * 19C4 * 15C5 * 10C5

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