Question

in how many ways can 3 women be selected out of 15 women if one particular woman is always included and two particular women are always excluded?​

Answer 1

Answer:

66 ways

Step-by-step explanation:

total women = 15

2 particular women is always excluded

then 13 women left to be choosen

Now 1 particular women is always included

then we have to choose 2 women out of 12 women that can be determined by formulae

12C2 = 12!/((12-2)!×2!)

(12×11×10!)/10!×2

12×11/2

66

total no. of ways =66.