Math, asked by madhuram8877, 11 months ago

In how many ways can 4 boys and 3 girls stand in a row so that no two girls are together?

Answers

Answered by architguptaom
0

Answer:

the answer is like that

Answered by divyabharti0842
0

Answer:

4320

Step-by-step explanation:

Here , we have to find the ways in which 4 boys and 3 girls can stand in a row such that no two girls are together.

Here no. of total person = 4+3

=7

So no. of ways = 7! - 3!×(7-3+1)!

= 5040 - 6×120

= 5040 - 720

= 4320

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