in how many ways can 4 boys and 4 girls be made to sit around a circular table if no two boys sit adjacent to each other
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Point to be noted: As it is a round table, the no.of possible ways are (n-1)! ways.
Condition is no two boys should sit adjacent to each other.
So, first arrange 4 girls in a round table such that they aren't adjacent to each other (as here, no. of boys = no.of girls)
So no.of possible ways arranging the girls in a round table = (4-1)! = 3! ways
Now, let the boys made to sit in the remaining gaps in 4! ways
Therefre total no.s of ways in which this condition is possible = 3! x 4! ways.
= 6 x 24 ways
= 144 ways.
Therefore, the no. of ways in which 4 boys and 4 girls can be made to sit around a circular table such that no two boys sit adjacent to each other are 144 ways.
Condition is no two boys should sit adjacent to each other.
So, first arrange 4 girls in a round table such that they aren't adjacent to each other (as here, no. of boys = no.of girls)
So no.of possible ways arranging the girls in a round table = (4-1)! = 3! ways
Now, let the boys made to sit in the remaining gaps in 4! ways
Therefre total no.s of ways in which this condition is possible = 3! x 4! ways.
= 6 x 24 ways
= 144 ways.
Therefore, the no. of ways in which 4 boys and 4 girls can be made to sit around a circular table such that no two boys sit adjacent to each other are 144 ways.
rishilaugh:
very nice answer
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1
Answer:
Each clockwise permutation has a matching anticlockwise ... there are 3 places for the other 3 boys that is 3! ... We have 4 ways of choosing a boy to sit ........................
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