Question

In how many ways can 4 people be seated in 3 chairs?

Answer 1

Here arrangement is occured. So 4P3 is the answer.

$^4P_3 \\ \\ = \frac{4!}{(4 - 3)!} \\ \\ = \frac{24}{1} = 24$

∴ 4 people can be seated in 3 chairs in 24 different ways.

Let's check.

Let the people be A, B, C and D.

Given below are the arrangements occured:

ABC

ABD

ACB

ACD

ADB

ADC

BAC

BAD

BCA

BCD

BDA

BDC

CAB

CAD

CBA

CBD

CDA

CDB

DAB

DAC

DBA

DBC

DCA

DCB

Hope this may be helpful.

Please mark my answer as the brainliest if this may be helpful.

Thank you. Have a nice day.