In how many ways can 4 people be selected from a group of 6 among which anil is one .how. many of these inclued anil ?
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I think the answer is 10.By keeping Anil constant in all the groups , remaining people are 5 and you can select only 3 of them . You need a group with 4 people .So if you apply the permutations and combinations logic here ,you have 5!/(5–3)!3! Which is equal to 10.
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hey your answer is here
think the answer is 10.By keeping Anil constant in all the groups , remaining people are 5 and you can select only 3 of them . You need a group with 4 people .So if you apply the permutations and combinations logic here ,you have 5!/(5–3)!3! Which is equal to 10.
think the answer is 10.By keeping Anil constant in all the groups , remaining people are 5 and you can select only 3 of them . You need a group with 4 people .So if you apply the permutations and combinations logic here ,you have 5!/(5–3)!3! Which is equal to 10.
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