in how many ways can 4 people be selected from a group of 6 among which anil is one . how many of these include anil
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In 5 ways 4 people can be selected
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keeping Anil constant in all the groups , remaining people = 5
you can select only 3 of them
you need a group with 4 people .
So if you apply the permutations and combinations logic here ,you have 5/(5–3)3
Which is equal to 10.
I think the answer is 10
Anonymous:
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