Math, asked by RSB11, 1 year ago

In how many ways can 4 prizes be given to 3 boys , if each boy is eligible for all prizes

Answers

Answered by dhruvsh
5
Let the 3 boys be B1, B2, B3 and 4 prizes be P1, P2, P3 and P4.

Now B1 is eligible to receive any of the 4 available prizes (so 4 ways).

B2 will receive prize from rest 3 available prizes(so 3 ways).

B3 will receive his prize from the rest 2 prizes available(so 2 ways).

So total ways would be: 4*3*2*1=24 Ways.

Hence, the 4 prizes can be distributed in 24 ways.

RSB11: 4!/2!
dhruvsh: Yep right
RSB11: =4×3×2×1/2×1
RSB11: =24
dhruvsh: Ohh noo! !!!
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