In how many ways can 4 prizes be given to 3 boys , if each boy is eligible for all prizes
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Let the 3 boys be B1, B2, B3 and 4 prizes be P1, P2, P3 and P4.
Now B1 is eligible to receive any of the 4 available prizes (so 4 ways).
B2 will receive prize from rest 3 available prizes(so 3 ways).
B3 will receive his prize from the rest 2 prizes available(so 2 ways).
So total ways would be: 4*3*2*1=24 Ways.
Hence, the 4 prizes can be distributed in 24 ways.
Now B1 is eligible to receive any of the 4 available prizes (so 4 ways).
B2 will receive prize from rest 3 available prizes(so 3 ways).
B3 will receive his prize from the rest 2 prizes available(so 2 ways).
So total ways would be: 4*3*2*1=24 Ways.
Hence, the 4 prizes can be distributed in 24 ways.
RSB11:
4!/2!
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