In how many ways can 5 boys and 3 girls be arranged in a row such that all the boys are together
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=(5×4×3×2×1)=120. Number of ways in which 3 girls can be arranged at 6 places (each marked X) =6P3=(6×5×4)=120.
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=(5×4×3×2×1)=120. Number of ways in which 3 girls can be arranged at 6 places (each marked X) =6P3=(6×5×4)=120.
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