Question

In how many ways can 5 children be arranged in a row such that no two boys akshay and aryan always sit together?
(with reference to permutations)​

Answer 1

Given:

Number of children = 5

To find:

Number of ways in which the children can be arranged so that Akshay and Aryan never sit together.

Solution:

Number of ways of arranging 5 children in a row = 5!

Number of ways of arranging children so that Akshay and Aryan always sit together = 4!*2!

Number of ways of arranging children so that Akshay and Aryan do not sit together = 5! - 4!*2!

= 120 - 48

= 72

Therefore the number of ways required will be 72.