Question

In how many ways can 5 girls and 3 boys be seated in a row such that no two boys are togethwr

Answer 1

First fix the girls = 5!

Then ways to insert 3 boys between 5 girls is = 6 choose 3 = 6!/(3! x 3!)

Therefore total ways = 5! * 6!/(3! x 3!)

= 5! * 20 ways