IN HOW MANY WAYS CAN 5 PRIZES BE DISTRIBUTED AMONG 4 STUDENTS, WHEN EACH STUDENT MAY RECEIVE ANY NUMBER OF PRIZES...?
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Answered by
1
1024
How many ways can 5 prizes be distributed among 4 students, where each is eligible for all the 5 prizes ? (i.e. repetition allowed) The answer says 1024, which I guess is coming from 45. So its like "4 students fit into each prize" + repeats allowed + 5 prizes =45=1024.
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Answered by
2
Answer:
1024
Step-by-step explanation:
First prize can be given to any one of the 4 boys, so it can be given in 4 ways. Second prize can also be given in 4 ways, as the boy getting first prize can also get the second. Similarly, third prize can be given in 4 ways and so on.
Hence, the total number of ways in which a boy can get any number of prizes = 4 × 4 × 4 x 4 x 4 =1024.
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