Question

In how many ways can 5 prizes be given away
to 4 boys when (i) each boy is eligible for all
the prizes (ii) A particular boy is not eligible
for all prizes.​

Answer 1

Answer:

There are 4 prizes to be given to 3 boys.

The first prize can be given to any of the 3 boys =

3

C

1

​

=3 ways.

Similarly the other 3 prizes cab be given to any of the 3 boys.

Total no. of permutations =3×3×3×3=3

4

=81

Hence, the answer is 81.

Step-by-step explanation:

Answer 2

Step-by-step explanation:

There are 4 prizes to be given to 3 boys.

The first prize can be given to any of the 3 boys =

3C^ 1=3 ways.

Similarly the other 3 prizes cab be given to any of the 3 boys.

Total no. of permutations =3×3×3×3=3 ^4 =81

Hence, the answer is 81