Question

in how many ways can 576 be expressed as a product of two distinct factors

Answer 1

In two ways prime factorisation and long division.

Answer 2

Answer:

factorization of 576 = 2*2*2*2*2*2*3*3

2^6 * 3^2

a^p b^q c^r

(p+1)(q+1)(r+1)

(6+1)(2+1)

7*3 =21

we have to divide it by 2 but in case if we get odd number need we have to make it even first.

if odd number comes just subtract with -1 to make it even and divide by 2:

(21-1)/2 = 10

Note:

if in case you get even number do not need to subtract by 1 just divide the output by 2

ex:  if we would have get 20 instead of 21 directly we can divide 20/2=10