Question

IN HOW MANY WAYS CAN 6 BOYS AND 6 GIRLS BE SEATED AROUND A TABLE SO THAT NO 2 BOYS ARE ADJACENT​

Answer 1

Answer:

Totally 12 members have to sit around table.

Totally 12 members have to sit around table.Let us assume 12 positions(1–12).

Totally 12 members have to sit around table.Let us assume 12 positions(1–12).Let’s place a boy in one position and shuffle remained ones around him.

Totally 12 members have to sit around table.Let us assume 12 positions(1–12).Let’s place a boy in one position and shuffle remained ones around him.As if no two boys should sit together,there is only way for them to place all the boys is placing alternately.

Totally 12 members have to sit around table.Let us assume 12 positions(1–12).Let’s place a boy in one position and shuffle remained ones around him.As if no two boys should sit together,there is only way for them to place all the boys is placing alternately.Now sguffling these 5 boys (excluding initially placed one because it doesn’t matter where ever we place him) gives us 5! possibilities.

Totally 12 members have to sit around table.Let us assume 12 positions(1–12).Let’s place a boy in one position and shuffle remained ones around him.As if no two boys should sit together,there is only way for them to place all the boys is placing alternately.Now sguffling these 5 boys (excluding initially placed one because it doesn’t matter where ever we place him) gives us 5! possibilities.And for six girls we have 6! possibilities.

Totally 12 members have to sit around table.Let us assume 12 positions(1–12).Let’s place a boy in one position and shuffle remained ones around him.As if no two boys should sit together,there is only way for them to place all the boys is placing alternately.Now sguffling these 5 boys (excluding initially placed one because it doesn’t matter where ever we place him) gives us 5! possibilities.And for six girls we have 6! possibilities.Therefore total number of ways are 5!×6!

Totally 12 members have to sit around table.Let us assume 12 positions(1–12).Let’s place a boy in one position and shuffle remained ones around him.As if no two boys should sit together,there is only way for them to place all the boys is placing alternately.Now sguffling these 5 boys (excluding initially placed one because it doesn’t matter where ever we place him) gives us 5! possibilities.And for six girls we have 6! possibilities.Therefore total number of ways are 5!×6!=86400.