In how many ways can 6 people sit around a table if 2 people must sit together?
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Since two people must be together, let's take them as if they were one person, then the total permutations are ((6 – 1) - 1)! = 4! = 24. But for each configuration, that pair can sit in two differente ways, then thte solution is 24 * 2 = 48.
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