In how many ways can 7 indians, 5 pakistanis and 6 dutch be seated in a row so that all persons of the same nationality sit together? 3!
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Answer:
answer is 3! × 7! × 6! × 5!.
Step-by-step explanation:
We need to assume that the 7 Indians are 1 person, so also for the 6 Dutch and the 5 Pakistanis. These 3 groups of people can be arranged amongst themselves in 3! ways. Also, within themselves the 7 Indians the 6 Dutch and the 5 Pakistanis can be arranged in 7!, 6! And 5! ways respectively. Thus, the answer is 3! × 7! × 6! × 5!.
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