In how many ways can 7 people be seated around a circular table such that 2 of them are always together
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Take together persons as one,
now number of ways of arranging 6 persons in circle=(n-1)!=5!
we need also to find arrangements of persons together,i.e.=2!
So required ways=5!*2!=120*2=240
now number of ways of arranging 6 persons in circle=(n-1)!=5!
we need also to find arrangements of persons together,i.e.=2!
So required ways=5!*2!=120*2=240
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