Question

in how many ways can 7 persons be seated around two circular tables when 4 persons canston the first table and 3 cansiton the other?​

Answer 1

Answer:

420

Step-by-step explanation:

here are total 7 persons.

From the 7 persons, 4 for the first table can be chosen in (7C4) ways

= (7!) / [(4!) * {(7 - 4)!}] ways = [(7!) / {(4!) * (3!)}] ways

= 35 ways.

And, those selected four persons can be arranged around the first round table in {(4 - 1)!} ways

= (3!) ways

= 6 ways.

Lastly, the remaining three persons can be arranged around the second round table in {(3 - 1)!} ways

= (2!) ways

= 2 ways.

Therefore, the final answer will be (35 * 6 * 2) = (35 * 12) = 420.