Question

in how many ways can 9 female and7 male members be selected for a review from a review team from a group of 15 females and 10 males?(in permutationsand combinations)​

Answer 1

Answer:

9450 ways..

Step-by-step explanation:

Assuming the female reviewers select females and males the same.

⇒15 x 9 = 135

⇒7 x 10 = 70

⇒70 x 135 = 9450

∴possible ways that the 9 female and 7 male members can be selected.

hope it helps!!!

Answer 2

Answer:

The number of ways of selecting 9 females and 7 males from the team is 5125.

Step-by-step explanation:

Given,

In a team, there are 15 females and 10 males.

To find,

The number of ways of selecting 9 females and 7 males from the team.

Calculation,

Let the number of ways of selecting 9 females from 15 females be 'x'

First, we calculate the number of ways of selecting 9 females from 15 females.

i.e. x =  $^{15}C_9$ = $\frac{15!}{(15! - 9!)\times 9!}$ = 5005

Let the number of ways of selecting 7 males from 10 males be 'y'.

First, we calculate the number of ways of selecting 7 males from 10 males.

i.e. y =  $^{10}C_7$ = $\frac{10!}{(10! - 7!)\times 7!}$ = 120

Hence, total number of ways = x + y = 5005 + 120 = 5125

Therefore, the number of ways of selecting 9 females and 7 males from the team is 5125.

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