Math, asked by sehgalmilan29, 4 months ago

In how many ways can a cricket team of 11 players be selected out of 16 players,

(i) If two particular players are always be included ?

(ii) If two particular players are always be excluded ​

Answers

Answered by VijayKumar1907
3

Answer:

Step-by-step explanation:

11 players can be selected out of 16 in 16C11 ways = 16!/(11! 5!) = 4368 ways. Now,

If two particular players is to be included and two particular player is to be rejected, then we have to select 9 more players out of 13 in 13C9 ways.

= 13!/(9! 4!) = 715 ways.

Answered by aarush113
13

11 players can be selected out of 16 in 16C11 ways = 16/(11 ! 5) = 4368 ways. Now,

If two particular players is to be included and if two particular players are always be excluded then we have to select 9 more players out of 13 in 13C9 ways.

= 13!/(9! 4!) = 715 ways.

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