In how many ways can a number 70562 be written as a product of two different factors
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Step-by-step explanation:
Factorising 6084 :
6084 = 2^2 x 3^2 x 13^2
If N = a^p b^q c^r, where a,b,c are primes,
Number of factors is represented by :
(p+1)(q+1)(r+1)
=> (2+1)(2+1)(2+1) = 27
Number of Ordered pairs of any two factors is ( 27 + 1)/2 = 14
Since 6084 is a perfect square, evidently the ordered pair (78,78) is also counted in the above 14 pairs.
So, the number of ways in which 6084 can be expressed as a product of two different factors is 13.
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