Math, asked by alpananayak2679, 1 year ago

In how many ways can a number 70562 be written as a product of two different factors

Answers

Answered by amritaraj
0

Answer:

Step-by-step explanation:

Factorising 6084 :

6084 = 2^2 x 3^2 x 13^2

If N = a^p b^q c^r, where a,b,c are primes,

Number of factors is represented by :

(p+1)(q+1)(r+1)

=> (2+1)(2+1)(2+1) = 27

Number of Ordered pairs of any two factors is ( 27 + 1)/2 = 14

Since 6084 is a perfect square, evidently the ordered pair (78,78) is also counted in the above 14 pairs.

So, the number of ways in which 6084 can be expressed as a product of two different factors is 13.

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