In how many ways can a team of 5 persons can be formed out of a total of 10 persons such that two particular persons should be included in each team?
Answers
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0
I think 11 person is your answer
.
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Answered by
0
Answer:
56 is answer
Step-by-step explanation:
Two particular persons should not be included in each team.
i.e., we have to select 5 persons from 10-2 = 8 persons.
Hence, required number of ways
= 8C5
= 8C3[∵ nCr = nC(n-r)]
=
8
×
7
×
6
3
×
2
×
1
=
8
×
7
=
56
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