Question

in how many ways can a team of 5 players be selected from 8 players so as not to include a particular player?​

Answer 1

$\huge \mathfrak \red{answer}$

if none of them is selected then there is only one combination of 8–3=5 persons. 2. In all other case we want all three , so assuming them one , we have 5 other persons and we have to select 20 out of them. So such combinations will be 5c2=5*4/(2*1)=10, hence total options are=10+1=11.

[/tex]

Answer 2

Answer:

A particular player shldnt be included
therefore we have to select 5 player from (8-1) = 7 players
therefore required no. of ways = C (7,5) = 21
therefore total 21 ways