In how many ways can be letter of the word TABLE be arranged so that the vowels are always (1)together (2) separated
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Total no. of vowels in TABLE = 2
Total no. of consonants in TABLE = 3
Here all the vowels and consonants are distinct.
If the vowels are together considered as a single object, then there'll be 4 letters in the word.
Then the no. of arrangements in which vowels are together is,
4 × 3! × 2! = 48
Total no. of possible arrangements with no condition = 5! = 120
Then, the required no. of arrangements in which vowels are separated = 120 - 48 = 72
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