In how many ways can for distinguishable pieces be placed on an 8 × 8 chess board so that no two pieces are in the same row or column?
Answers
Answered by
14
Answer:
the 1st piece can be placed in 64 ways, but 1 row & 1 column get eliminated so the next piece can only be placed in 49 ways, & so on
8² x 7² x 6² x 4² = (8P4)² = (8!/4!)² <------
Step-by-step explanation:
plz mark me brainlist
Similar questions