Math, asked by sovi8779, 1 year ago

In how many ways can seven friends be seated in a row having 35 seats, such that no two friends occupy adjacent seats?
A.29P7
B.29C7
C.28P7
D.28C7

Answers

Answered by genious2000
2

Answer:

A. 29P7 is the answer.

Step-by-step explanation:

Let us consider the 28 unoccupied seats.

They create 29 slots: one on the left of each seat and one on the right of the last one.

We can place the 7 friends in any of these 29 slots i.e. 29P7 ways.

Answered by Jamestiwari
0

Consider 28 unoccupied seats

29 seats are created - on the left and one on the right of the last seat .

we can place seven friends in any of the 29 slots

i.e. 29P7

#SPJ2

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