Question

In how many ways can the digits of the number 2233558888 be arranged so that the odd digits is placed in the position

Answer 1

Answer:

Therefore no. of possible arrangements = 450

Explanation:

Even positions = 5

so the numbers can be placed in 5! ways and 3 is repeated twice and also 5 is repeated twice so...

$\frac{5!}{2!*2!} =30$

after 4 odd nos are placed then we have 6 positions for other nos to be placed so...same as 6!  ways and 2 is repeated twice and 8 is repeated four times...

$\frac{6!}{2!*4!} = 15$

so 30*15=450