In how many ways can the letters a, a, b, b, b, c, d, e be arranged if the letter c must be to the right of the letter d?
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Answer:
48+7= 55 ways
Step-by-step explanation:
Each letter can be arranged 8 times.(except d,c)
So, There are altogether 6 letters that can be arranged 8 times. (except d,c)
Thus, the no. of rearrangements that can be made are 8 X6=48 times
Now, the letters (d, c) can be arranged together in certain way by 7 times.
HENCE,
ALL THE LETTERS IN CERTAIN WAY CAN BE ARRANGED IN 48+7 = 55 WAYS
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