Math, asked by geetadubla795, 5 months ago

In how many ways can the letters of the word FORTUNE be arranged ? How many of
these (i) begin with F and end with E ? (ii) have T in the middle position ? (iii) vowels
in the first three positions (iv) vowels in the second, third and fourth position in the
order O, U, E?
5 if​

Answers

Answered by Ahanam57
4

Well,It's a very tricky question.

N I'm sry for not being able to answer it..

But pls follow me so that I can help you next time onwards..

Answered by mathcult
0

Answer:

Step-by-step explanation:

(i) the word F O R T U N E has 7 letters out of which the placing of 2 letters f and e is already reserved as 1st and last place respectively. So,

number of possible arrangements= (7-2)! ÷ 2! = 5! ÷ 2! = 5×4×3 = 60

                                                       

Similar questions