In how many ways can the letters of the word FORTUNE be arranged ? How many of
these (i) begin with F and end with E ? (ii) have T in the middle position ? (iii) vowels
in the first three positions (iv) vowels in the second, third and fourth position in the
order O, U, E?
5 if
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Answer:
Step-by-step explanation:
(i) the word F O R T U N E has 7 letters out of which the placing of 2 letters f and e is already reserved as 1st and last place respectively. So,
number of possible arrangements= (7-2)! ÷ 2! = 5! ÷ 2! = 5×4×3 = 60
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