In how many ways can two 10 paise two 20 paisa three 25 paise and one 50 paisa coins be distributed among 8 children so that each student get only one coin
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Answer:
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Explanation:
Total number of coins =2+2+3+2=8
2 coins are 10 paise, 2 are 20 paise, 3 are 25 paise and 1 is of 50 paise.
∴ Required number of ways
=
2!×2!×3!×1!
8!
=
2×1×2×1×3×2×1×1
8×7×6×5×4×3×2×1
=8×7×6×5=1680
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