in how many ways can we distribute 5 apples. 6 bananas and 7 cherries among 2 people such that each person gets atleast one fruit ?
(ans 334 i don't know the way of doing) help!!
Answers
Given : 2 person for distribution
total fruit = 5 apple+ 6 Banana +7 cherry = 18 item
Solution :
soory brother lot of confution...
but definitely total number of ways is 336 and 2 possiblity any one person get 0 fruit this is minimise from it..
Answer:
We can absolutely distribute three fruits to two persons in 334 different ways (as your response to this question indicates ), but how? Let's look at this strategy step by step.
Step-by-step Explanation:
There are 5 apples, 6 bananas, and 7 cherries, according to this question.
Now imagine there are three packages in front of us, where the first package holds five apples, the second package contains six bananas, and lastly, the third package has seven cherries.
Now, from the 1st package, you can select either 1 or 2 or 3 or 4 or 5 or none of the apples..so we'll get 6 cases
From the 2nd package, you can select either 1 or 2 or 3 or 4 or 5 or none of the bananas..so we'll get up to 7 cases.
Similarly, in the 3rd package, we would select and proceed to the same calculation of these cases, provided above - we'll get approx. 8 cases
Thus, in all packages, we'll estimate the Total selections of 3 packages which we get = 6*7*8 = 336
Now, we'll also include the estimation of such cases, where we might have none of these 3 kinds of fruits that we've selected. So, according to that, we'll subtract that case, after that we'll get =
Total required cases (or as the cases where we want to distribute to two people's which each person gets at least one of the fruit )
= 336 – 2 = 334 ways
Now, here is the specific method by which you'll get that accurate answer, just as you've mentioned in question previously.
For more questions like this, please refer - https://www.quora.com/In-how-many-ways-can-we-distribute-7-apples-and-6-oranges-among-4-children-so-that-each-child-gets-at-least-one-fruit