In how many ways can we get a total of 15 if three distinguishable dice are rolled?
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Total Possible Combinations of Getting total of 15 is
a) (3,6,6) so total ways of getting this combination is 3! /2! = 3
b) (4,6,5) similarly no of ways of getting this combination= 3! =6
c) (5,5,5) so total ways of getting this combination 3! /3! = 1
Total Possible Ways = 3+6+1= 10
Or you can count like this : (6,6,3),(6,5,4),(6,4,5),(6,3,6),(5,6,4),(5,5,5),(5,4,6),(4,6,5),(4,5,6) and (3,6,6).
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