Question

In how many ways, can we select a team of 4 students from a given choice of 15 ?

Answer 1

See the attach file for ur ans

Answer 2

Answer:

Number of possible ways of selection

$=(15 \times 14 \times 13 \times 12) /(4 \times 3 \times 2 \times 1)=1365$ ways.

Step-by-step explanation:

A permutation exists as an act of placing the objects or numbers in order. Combinations exist as a method of determining the objects or numbers from a grouping of objects or collections, in such a way that the order of the objects does not matter.

In combination and permutation exist two various forms of grouping features of a set into subsets. In a combination, the elements of the subset can be documented in any order. In a permutation, the elements of the subset exist recorded in a specific order.

A number of possible ways of selection $=15 C_{4}=15$ ! $/ [(4!) x(11 !)$

Number of possible ways of selection

$=(15 \times 14 \times 13 \times 12) /(4 \times 3 \times 2 \times 1)=1365$ ways.

SPJ2