Question

In how many ways
committee of 5 student
can be formed from 6 boys & 7 girls?​

Answer 1

Answer:

girls and (5–2=3) boys.

So 2 girls can be chosen from 4 in 4c2 ie 6 ways.

For each of those 6 selections, 3 boys can he cuosen from 6 in 6c3 ie 20 ways.

So total selections for the favorable cases= 6*20=120

The sample space will contain the number of cases of 5 member selection from 6 boys and 4 girls ie (6+4=10) students which is 10c5 = 252

So required probability = (favorable cases) / (sample space) = 120/252 = 10/21

I hope it's helpful for you