In how many ways e is always after a pemutaions and combinations
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☆☆heya your answer is here☆☆
solution:--
Permutation:
P(n,r)=n!(n−r)!P(n,r)=n!(n−r)!
Combination:
C(n,r)=n!(n−r)!r!C(n,r)=n!(n−r)!r!
Apparently, you use combination when the order doesn't matter. Great. I see how a combination will give you all the possible well, combinations. However, I don't see what exactly does a permutation do then.
solution:--
Permutation:
P(n,r)=n!(n−r)!P(n,r)=n!(n−r)!
Combination:
C(n,r)=n!(n−r)!r!C(n,r)=n!(n−r)!r!
Apparently, you use combination when the order doesn't matter. Great. I see how a combination will give you all the possible well, combinations. However, I don't see what exactly does a permutation do then.
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